Answer:
A)x^2-x-6
B)2x^2-12x+12
C)x^2-4
Step-by-step explanation:
A) Lets break this problem into portions the first part we trying to distribute is x(x-3)
X times X is X^2 and X times 3 is 3x so x^2-3x
Lets work on the second part
2(x-3)
2 times x =2x and 2 times -3 = -6 so 2x-6
And since you are supposed to add them its 2x-6+x^2-3x
x^2 can't be combined so that is seperate but 2x(+)-3x (negative overpowers positiveis) so we have -x and then -6 cant be joined with anything so
x^2-x-6
B) I'm going to go a little faster but it's essentially the same
2x(x-4)-3(x-4)
Multiply2x*x= 2x^2
2x*-4=-8x
combinde these two (2x^2-8x)
Pt.2
-3*x= -3x
-3*-4(negative and negative cancels out and it becomes positive)=12
join (-3x+12)
and then 2x^2-8x-3x+12
you can only combine -8x-3x so -12x
2x^2-12x+12
C) this is level 3
x(x-2) + 2(x-2)
(x^2-2x) +(2x-4)
only like terms is 2x and-2x so combine and its 0
x^2-4
