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Which series of transformations takes the graph of f(x)=3x−8 to the graph of g(x)=−3x+12 ?

A.) reflect the graph about the y-axis and translate 4 units down

B.) reflect the graph about the y-axis and translate 4 units up

C.) reflect the graph about the x-axis and translate 4 units down

D.) reflect the graph about the x-axis and translate 4 units up

Respuesta :

 reflect the graph about the x-axis and translate 4 units down 

D.) reflect the graph about the x-axis and translate 4 units up

Explanation:

Before to identify the correct choice, let's see the definition of reflection along the x-axis and the y-axis:

1- A reflection of [tex]f(x)[/tex] about the x-axis can be done by changing [tex]f(x)[/tex] into [tex]-f(x)[/tex]. This means that if we have a line in the form

[tex]y=mx+q[/tex]

a reflection about the x-axis can be done by changing the function into

[tex]y=-mx-q[/tex]

2- A reflection of [tex]f(x)[/tex] about the y-axis can be done by changing [tex]f(x)[/tex] into [tex]f(-x)[/tex]. This means that if we have a line in the form

[tex]y=mx+q[/tex]

a reflection about the x-axis can be done by replacing all the x with -x:

[tex]y=-mx+q[/tex]

Back to our exercise:

The original function is [tex]f(x)=-3x-8[/tex]. The final function is [tex]g(x)=-3x+12[/tex]. First of all, we immediately notice that both the signs of m and q have been changed: therefore, it must be a reflection about the x-axis, so we can discard option B.

The reflection of f(x) about the x-axis is

[tex]f'(x)=-3x+8[/tex]

We see that the y-intercept is +8, while in g(x) the y-intercept is +12. In order to match the two functions, we must translate f'(x) up by 4 units, so that we get

[tex]f'(x)+4=-3x+8+4=-3x+12[/tex]

which corresponds to g(x). So, the correct option is D.