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A current of 9 A flows through an electric device with a resistance of 43 Ω. What must be the applied voltage in this particular circuit?


A. 387 V
B. 4.8 V
C. 387 A
D. 4.8 A

( the answer choice ; "A." 387 V , was marked incorrect. )

Respuesta :

Answer: Option (A) is the correct answer.

Explanation:

Ohm's law states that current passing through a circuit is directly proportional to the voltage over resistance.

Mathematically,       [tex]I = \frac{V}{R}[/tex]

where,      I = current

                V = voltage

                 R = resistance

It is given that electric device has current of 9 A and resistance of 43 ohms. Therefore, calculate the voltage as follows.

                      [tex]I = \frac{V}{R}[/tex]

or,                  [tex]V = I \times R[/tex]

                                 = [tex]9 Ampere \times 43 \frac{Volts}{Ampere}[/tex]

                                 = 387 V

Thus, we can conclude that the applied voltage in this particular circuit is 387 V.