Respuesta :
okay well
a(t)= amount of substance remaining after t days
assuming exponential decay, a(t)=29e^-0.1359t
now, find the half, set a(t)= half the original and solve for t
14.5=29e^-0.1359t
0.5=e^-0.1359t
In(0.5)=In(e^-0.1359t)
In(0.5)=-o.1359t
t=in(0.5)/(-0.1359)= (aprox) 5.1 days
a(t)= amount of substance remaining after t days
assuming exponential decay, a(t)=29e^-0.1359t
now, find the half, set a(t)= half the original and solve for t
14.5=29e^-0.1359t
0.5=e^-0.1359t
In(0.5)=In(e^-0.1359t)
In(0.5)=-o.1359t
t=in(0.5)/(-0.1359)= (aprox) 5.1 days