Can you check my answers? Thanks!!!! What would happen to the volume-to-temperature ratio if:
1. One student failed to replenish the boiling water in the boiling-water bath as the flask was being heated. At the end of the 6 min of heating, the boiling water in the bath was only in contact with the lower portion of the flask.
2.Following the proper heating of the flask in the boiling water, a student removed the flask from the boiling-water bath but only partially immersed the flask in the ice-water bath during the cooling period.
3.A student neglected to close the pinch clamp before removing the flask from the boiling-water bath and immersing it in the ice-water bath.
4. One student neglected to measure the volume of the flask before leaving the laboratory. Because the procedure called for a 125-mL Erlenmeyer flask, the student used 125 mL as the volume of the flask.
My answers: 1. It would be lower 2. It would be lower 3. It would be higher 4. It would be higher. Thank you!!!

Respuesta :

What would happen to the volume-to-temperature ratio if:

1. Lower ratio, because the volume of the system is lower than the temperature.

2. Lower,  since the volume is still small as compared to temperature

4. Higher, the system has a higher value of volume.

Answer:

Volume-to-temperature ratio would be lower.

Volume-to-temperature ratio would be higher.

Volume-to-temperature ratio would be higher.

Volume-to-temperature ratio would be lower.

Explanation:

1. The temperature of the water would increase but as the water bath was boiling there was phase change turning water to steam decreasing the volume but increasing the temperature.

So the volume-to-temperature ratio would be lower.

2. As the flask is cooled in ice the volume decreases by a small amount and temperature decreases.

So the volume-to-temperature ratio would be higher.

3. The volume would decrease due to evaporation but air will enter increasing the volume and temperature is increasing

So the volume-to-temperature ratio would be higher.

4. After these above processes definetly there will be a loss of volume.

So the volume-to-temperature ratio would be lower.