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To determine the one with the greatest mass, we convert all options into the same units of mass as follows:

1. 3.55 mol O atoms ( 16 g / mol ) = 56.8 g O
2. 4.52 g O atoms 
3. 0.0032 kg O2 molec ( 1000 g / 1kg ) ( 1 mol / 32 g ) ( 2 mol / 1 mol ) ( 16 g / mol) = 3.2 g O
4. 7.39 × 10^23 O2 molec ( 1 mol / 6.022x10^23 molecules) (2 mol / 1 mol)(16 g/mol) = 39.27 g O

Answer: The correct answer is Option 1.

Explanation:

For the given options:

  • Option 1:  3.55 mole of O atoms

To calculate the number of moles, we use the equation:

[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}[/tex]

Moles of Oxygen = 3.55 mol

Molar mass of Oxygen = 16 g/mol

Putting values in above equation, we get:

[tex]3.55=\frac{\text{Mass of oxygen}}{16g/mol}\\\\\text{Mass of oxygen}=56.8g[/tex]

Mass of oxygen atoms = 56.8 g

  • Option 2: 4.52 g of O atoms

Mass of oxygen atoms = 4.52 g

  • Option 3: 0.0032 kg of [tex]O_2[/tex] molecule

Converting this into grams, we use the conversion factor:

1 kg = 1000 g

So, 0.0032 kg = 3.2 g

Mass of [tex]O_2[/tex] molecule = 3.2 g

  • Option 4: [tex]7.39\times 10^{23}[/tex] of [tex]O_2[/tex] molecule

According to mole concept:

1 mole of an atom contains [tex]6.022\times 10^{23}[/tex] number of atoms.

If, [tex]6.022\times 10^{23}[/tex] number of atoms occupies 32 grams of oxygen molecule.

So, [tex]7.39\times 10^{23}[/tex] number of atoms will occupy = [tex]\frac{32g}{6.022\times 10^{23}}\times 7.39\times 10^{23}=39.2g[/tex]

Mass of [tex]O_2[/tex] molecule = 39.2 g

Hence, the greatest mass is coming out from option 1.

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