Respuesta :
if they add to get a positive answer and multiply up to a positive number, both of them are positive
if they add to a negative answer and multiply to a positive, both of them are negative
if they add to a negative and multiply to a negative, one of them is positive and one of them is negative.
if they add to a positive and multiply to a negative, one of them is positive and one of them is negative.
with this information, we know your answer is both negative answers.
however i am not sure if the answer is whole because i have -10 and -2 to be -20 but -11 and -1 is -11, so the answer is between there.
if they add to a negative answer and multiply to a positive, both of them are negative
if they add to a negative and multiply to a negative, one of them is positive and one of them is negative.
if they add to a positive and multiply to a negative, one of them is positive and one of them is negative.
with this information, we know your answer is both negative answers.
however i am not sure if the answer is whole because i have -10 and -2 to be -20 but -11 and -1 is -11, so the answer is between there.
Factorising 2x^2-13x+18
2x^2-13x+18 is a quadratic in the form ax^2+bx+c. The first step to factorise it is to write out the factors of the c term, the factors of +18 are +/-1 and +/-18, +/-2 and +/-9, or +/-3 and +/-6. We know that one of these sets of factors will be the 2 constants in the factorised double brackets form of this function, to find out which set of factors we see which factors will add together to equal b, although because a=2 one of the factors is multiplied by 2 so actually we want to find out which set of factors add together to equal b when one of the factors is multiplied by 2, b=-13, and 2(-2)+(-9) =-13, so the 2 factors are -2 and -9, the next step is to put them in the brackets and don't forget the 2 has to be on one of the x's, and -2 has to be in the opposite bracket, 2x^2-13x+18=(2x-9)(x-2)
2x^2-13x+18 is a quadratic in the form ax^2+bx+c. The first step to factorise it is to write out the factors of the c term, the factors of +18 are +/-1 and +/-18, +/-2 and +/-9, or +/-3 and +/-6. We know that one of these sets of factors will be the 2 constants in the factorised double brackets form of this function, to find out which set of factors we see which factors will add together to equal b, although because a=2 one of the factors is multiplied by 2 so actually we want to find out which set of factors add together to equal b when one of the factors is multiplied by 2, b=-13, and 2(-2)+(-9) =-13, so the 2 factors are -2 and -9, the next step is to put them in the brackets and don't forget the 2 has to be on one of the x's, and -2 has to be in the opposite bracket, 2x^2-13x+18=(2x-9)(x-2)