Respuesta :
Explanation:
Molar mass of [tex]KClO_{3}[/tex] = 39.1 + 35.5 + 3(16.0) = 122.6 g
Molar mass of KCl = 39.1 + 35.5 = 74.6 g
Molar mass of [tex]O_{2}[/tex] = 32.0 g
According to the equation, 2 moles of [tex]KClO_{3}[/tex] reacts to give 3 moles of oxygen.
Therefore, 2 (122.6) = 245.2 g of [tex]KClO_{3}[/tex] will give 3 (32.0) = 96.0 g of oxygen. Thus, 245.2 g of [tex]KClO_{3}[/tex] gives 96.0 g of oxygen.
(a) Calculate the amount of oxygen given by 2.72 g of [tex]KClO_{3}[/tex] as follows.
[tex]\frac {96g}{245.2g} \times 2.72 g = 1.06 g[/tex] of [tex]O_{2}[/tex]
(b) Calculate the amount of oxygen given by 0.361 g of [tex]KClO_{3}[/tex] as follows.
[tex]\frac {96g}{245.2g} \times 0.361 g = 0.141 g[/tex] of [tex]O_{2}[/tex]
c) Calculate the amount of oxygen given by 83.6 kg [tex]KClO_{3}[/tex] as follows.
[tex]\frac {96g}{245.2g} \times 83.6 g = 32.731 kg[/tex] of [tex]O_{2}[/tex]
Convert kg into grams as follows.
[tex]\frac{32.731 kg}{1 kg} \times 1000 g[/tex] = 32731 g of [tex]O_{2}[/tex]
(d) Calculate the amount of oxygen given by 22.5 mg of [tex]KClO_{3}[/tex] as follows.
[tex]\frac {96g}{245.2g} \times 22.5 mg = 8.79 mg[/tex]
Convert mg into grams as follows.
[tex]\frac{8.79 mg}{1 mg}\times 10^{-3} g = 8.79 \times 10^{-3} g[/tex] of [tex]O_{2}[/tex]
