While watching a small fireworks display from a building 204 feet tall, you observe a rocket that travels from ground to eye level in 6 seconds, and explodes. What is the maximum speed that you can guarantee that the rocket reached?
204 ft = 62.2 m We know that the initial velocity of the rocket was 0, we can find its acceleration using: s = ut + 1/2 at² 62.2 = 0.5a(6)² a = 3.46 m/s² Now, the final velocity of the rocket: v = u + at v = 3.46 x 6 v = 20.76 m/s = 68.1 ft/s
