Respuesta :
y = x^3 + 5x + 1
y = x
When they are equal
x^3 + 5x + 1 = x
x^3 + 4x + 1 = 0
x(x^2 + 4) = -1
-0.25((-0.25)^2 + 4) = -0.25(0.0625 + 4) = -1.02
Therefore, the equation is equal at approximately x = -0.25
y = x
When they are equal
x^3 + 5x + 1 = x
x^3 + 4x + 1 = 0
x(x^2 + 4) = -1
-0.25((-0.25)^2 + 4) = -0.25(0.0625 + 4) = -1.02
Therefore, the equation is equal at approximately x = -0.25
Answer:
[tex]x=-0.25[/tex]
Step-by-step explanation:
we have
[tex]y=x^{3}+5x+1[/tex] -----> equation A
[tex]y=x[/tex] -----> equation B
Using a graphing tool-----> to resolve the system of equations
Remember that the solution of the system of equations is equal to the intersection point both graphs
see the attached figure
the solution is [tex]x=-0.25[/tex]
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