Answer:
One number is 11 and another is 5
Step-by-step explanation:
One number is 4 less than 3 times another number:
If we let "one number" be x, and
"another number" be y, we can write:
[tex]x=3y-4[/tex]
If their sum is 16:
This means if we add both the numbers, x & y, we get 16:
[tex]x+y=16[/tex]
Now substituting equation 1 into equation 2, we can solve for y:
[tex]x+y=16\\(3y-4)+y=16\\3y-4+y=16\\4y=16+4\\4y=20\\y=\frac{20}{4}=5[/tex]
Now substituting y=5 into equation 1, we can solve for x:
[tex]x=3y-4\\x=3(5)-4\\x=15-4\\x=11[/tex]
Hence one number is 11 and another is 5
