The answer is B, D, A, C.
1. [tex]x^{2} -8x-20= x^{2} +2x-10x-2*10= (x^{2} +2x)-(10x+2*10)= \\ =x(x+2)-10(x+2)=(x+2)(x-10)[/tex] (choice B)
2. [tex] x^{2} +8x-20= x^{2} +10x-2x-2*10=( x^{2} -2x)+(10x-2*10)= \\=x(x-2)+10(x-2)=(x-2)(x+10) [/tex] (choice D)
3. [tex]x^{2} -x-20= x^{2} -5x+4x-4*5= (x^{2} -5x)+(4x-4*5) = \\ =x(x-5)+4(x-5)=(x-5)(x+4)[/tex] (choice A)
4. This leaves the choice C.