P = ae^(kt); where P is the population after t hours, a is the initial population, k is the growth rate, and t is the time interval.
2400 = 2000e^(2k)
e^(2k) = 2400/2000 = 1.2
2k = ln 1.2
k = ln 1.2 / 2 = 0.0912
After 10, hours:
P = 2000e^(10 x 0.0912) = 2000e^0.912 = 4,979
