Each time you fold the piece of paper, you double its thickness. So we can write an equation to represent the thickness of the paper:
t=thickness
f=# of folds
t=0.0038(2)^f
Let's solve for f.
(2)^f = (t/0.0032)
f= log(base 2) of (t/0.0032)
The paper needs to be thicker than one mile- or, converted into inches, thicker than 63360 inches.
So, f = log(base 2) of (63360)/(0.0032)
f = 24.24
The paper must be thicker than one mile, and we can't have a friction for our answer, so we round up to the next greatest integer. The answer is 25 times.
Hope this helps!!
