hopeerkeneff hopeerkeneff

16-02-2021
Chemistry

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How many moles are contained in 7.88 x 10^24 atoms of Iron

Respuesta :

dunn2003 dunn2003

16-02-2021

Answer:

1.31 × 10^47

Explanation:

1 mol of Fe =

[tex]1 \: mol \: of \ fe = 6.02 \times 10 ^{23} \ \\ x \: mol \: offe \: = 7.88 \times {10}^{24} \\ \\ \\ so \: 7.88 \times {10}^{24} \div 6.02 \times {10}^{23} \\ \\ x = 1.31 \times {10}^{47} [/tex]

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