Two students, Abby and Melissa go for a walk. Abby begins walking 30 seconds earlier than Melissa .

-Abby walks at a speed of 8 feet per second.
-Melissa walks at a speed of 9 feet per second.

Abby had been walking for BLANK seconds when both students had walked exactly the same distance. (round to the nearest whole)
please help me

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Answer:

270 seconds

Step-by-step explanation:

Melissa's time = x seconds

Abby's time = (x + 30) seconds

Abby walks at a speed of 8 feet per second, and Melissa walks at a speed of 9 feet per seconds.

But, speed = [tex]\frac{distance}{time taken}[/tex]

For Abby,

8 = [tex]\frac{distance}{(x + 30)}[/tex]

distance = 8(x + 30) ................. 1

for Melissa,

9 = [tex]\frac{distance}{x}[/tex]

distance = 9x ............. 2

From equations 1 and 2, for the same distance;

8(x + 30) = 9x

8x + 240 = 9x

x = 240 seconds

Abby's time = (x + 30)

                    = (240 + 30)

                    = 270 seconds

So that Abby has been walking for 270 seconds when both students had walked exactly the same distance.

The time taken is 270 seconds.

Given that,

  • Two students, Abby and Melissa go for a walk.
  • Abby begins walking 30 seconds earlier than Melissa .
  • Abby walks at a speed of 8 feet per second.
  • Melissa walks at a speed of 9 feet per second.
  • Here we assume Melissa time be x and Abby time be x + 30

Based on the above information, the calculation is as follows:

8(x + 30) = 9x

8x + 240 = 9x

x = 240

So Abby time should be

= 240 +  30

= 270

Learn more: brainly.com/question/17429689