Answer:
The slope of the line [tex]m = -\frac{1}{2}[/tex]
The point ( x₁ ,y₁) = ( 2,1)
Step-by-step explanation:
Explanation:-
Given that the line
[tex]y -1 = -\frac{1}{2} ( x-2)[/tex]
Comparing y- y₁ = m(x-x₁)
The slope of the line [tex]m = -\frac{1}{2}[/tex]
The point ( x₁ ,y₁) = ( 2,1)
The equation of the straight line
[tex]y -1 = -\frac{1}{2} ( x-2)[/tex]
2(y-1) = -(x-2)
2y -2 = -x +2
x + 2y -2-2=0
x +2y -4=0
Final answer:-
The equation of the straight line x+ 2y-4=0
The slope of the line [tex]m = -\frac{1}{2}[/tex]
The point ( x₁ ,y₁) = ( 2,1)
