Anyone know how to do this?
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Answer:
third option
Step-by-step explanation:
The equation of quantities in direct variation is
y = kx ← k is the constant of variation
y = 3x ← is in this form with k = 3
Thus the function represents direct variation → I
The graph of the equation of direct variation passes through the origin II
When x = 2, then
y = 3 × 2 = 6 → IV