Answer:
22.1 g
Explanation:
Step 1: Write the balanced equation for the combustion of acetylene
2 C₂H₂ + 5 O₂ ⇒ 4 CO₂ + 2 H₂O
Step 2: Calculate the moles corresponding to 75.0 g of CO₂
The molar mass of CO₂ is 44.01 g/mol.
75.0 g × 1 mol/44.01 g = 1.70 mol
Step 3: Calculate the moles of C₂H₂ required to produce 1.70 moles of CO₂
The molar ratio of C₂H₂ to CO₂ is 2:4. The moles of C₂H₂ required are 2/4 × 1.70 mol = 0.850 mol.
Step 4: Calculate the mass corresponding to 0.850 moles of C₂H₂
The molar mass of C₂H₂ is 26.04 g/mol.
0.850 mol × 26.04 g/mol = 22.1 g
