Answer:0.250 mols
Explanation:
That’s the answer I got it wrong using the guy that previously wrote that the answer is 19 mols his totally wrong don’t trust him
We have that Moles that are present in 10, 0 grams of sodium hydroxide (NaOH ) is
Moles\ NaOH =0.25moles
From the question we are told
How many moles are present in 10, 0 grams of sodium hydroxide (NaOH )
Generally the equation for the Molar mass of sodium hydroxide is
[tex](NaOH) = (22.990 + 15.9994 + 1.008) \\\\ {(NaOH)} = 40 g/mol[/tex]
Where
Mass_{NaOH}taken = 10 g.
[tex]Moles\ NaOH =\frac{(mass of NaOH taken)}{(molar mass of NaOH)}\\\\Moles\ NaOH = \frac{10}{(40}\\\\Moles\ NaOH =0.25moles[/tex]
Therefore
Moles that are present in 10, 0 grams of sodium hydroxide (NaOH ) is
Moles\ NaOH =0.25moles
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