Zinc has a density of 7.10 g/cm3. If a cylinder of zinc weighing 46.77 g is completely immersed in a graduated cylinder that originally contains 33.33 mL of water, what will be the new water level? PLEASE HELP!!!! I NEED TO TURN THIS IN SOON!

Respuesta :

Zinc density = 7.10 = 46.77/x ==> x = 46.77/7.10 =6.6 cm3 or 6.6 ml
New water level = 33.33+ 6.6 = 39.93 ml
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The new water level will be 39.92 mL

The Density of a substance is simply defined as the mass of the subtance per unit volume of the substance i.e

Density = mass /volume

To solve the question given above, we'll begin by calculating the volume of the zinc. This can be obtained as follow:

Density of Zinc = 7.10 g/cm³

Mass of Zinc = 46.77 g

Volume of Zinc =?

Density = mass /volume

7.10 = 46.77 / Volume

Cross multiply

7.10 × Volume = 46.77

Divide both side by 7.10

Volume = 46.77 / 7.10

Volume of Zinc = 6.59 cm³

Finally, we shall determine the new volume of the water. This can be obtained as follow:

Volume of Zinc = 6.59 cm³ = 6.59 mL

Volume of water = 33.33 mL  

New volume of water =?

New volume of water = (Volume of Zinc) + (Volume of water)

New volume of water = 6.59 + 33.33

New volume of water = 39.92 mL

Therefore, the new volume of water is 39.92 mL

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