Respuesta :
Step-by-step explanation:
so we're making two draws *with* replacement (this is important)
step 1: for the first draw, it wants the probability of getting a sour candy. to calculate this:
(# of sour candy) / (total # of candy)
step 2: for the second draw, it wants the probability of *not* getting a sour candy. to calculate this, you can calculate 1 - (the probability form part 1).
step 3: to find the probability of both events happening together, simply multiply the probabilities from part 1 and 2 together
side note: for step 2, you can only do this because the candy is being replaced. if there were no replacement, you'd have to re-calculate (# of non-sour candies) / (total after the first candy is drawn)
Answer:
A. 23%
Step-by-step explanation:
Let's figure out how many pieces of candy there is in total:
10 + 12 + 6 = 28
In total, there are 28 pieces of candy.
Let's find the probability that a piece is sour:
[tex]\frac{10}{28} = \frac{5}{14}[/tex]
The probability of pulling a sour piece out of the bag is 5/14.
This means that the probability that the candy pulled is not sour is 9/15 (or simplified 3/5)
To find the probability that the first candy picked out is sour AND the second candy picked is not sour we have to multiply the probabilities of both:
[tex]\frac{5}{14} *\frac{3}{5} = 0.229 = 23[/tex]
Therefore, A. 23% is the correct answer.
Hope this helps!!
- Kay :)