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After the shuttle disaster, an unknown compound residue was removed from a piece of the debris. Upon analysis, it was found to contain 2.61 g of carbon, 6.09 g of nitrogen, and 1.31 g of hydrogen. What is its empirical formula?

Respuesta :

Answer:

The final empirical formula is [tex]C_2 N_5 H[/tex]

Explanation:

Given

The amount of carbon, nitrogen and hydrogen in a given compound is as follows

C:N:H

[tex]2.61 : 6.09 : 1.31[/tex]

On simplifying the ration values  we get

[tex]\frac{2.61}{1.31} : \frac{6.09}{1.31} : \frac{1.31}{1.31}[/tex]

So the final ratio is

[tex]2 : 5 : 1[/tex]

The final empirical formula is [tex]C_2 N_5 H[/tex]

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