Answer:
Hello your question is incomplete attached below is the complete question
answer: RS = ST ( option b )
Step-by-step explanation:
First we consider Δ SCA and Δ TCB
∠ SCA = ∠ TCB , ∠CAS = ∠CBT = 90°
if we assume RS = ST then ΔSRT will be termed an Isosceles triangle with its legs : SR = ST. also vertex S bisects the base of the triangle.
Δ SBR ≅ ΔSBT from here we can deduce that ; BR = BT
From the assumptions what is actually missing to contrast the proof is : RS = ST
