Answer:
Potential Energy = 147Joules
KE = 490Joules
Explanation:
1) Potential Energy = mgh
Mass m = 50kg
g = 9.8m/s^2
height h = 3.0m
Potential = 50*9.8*3
Potential Energy = 147Joules
2) KE = 1/mv^2
Get the velocity
v² = u²+2gh
v² = 0²+2(9.8)(1.0)
v² = 19.6
v = √19.6
v = 4.43m/s
KE = 1/2 * 50 *4.43²
KE = 25 * 19.6
KE = 490Joules
Hence the kinetic energy is 490Joules
(a) The potential energy of the can when it is at the top of the ladder is 1470 J.
(b) The kinetic energy of the can when it is 1.0 meter above the floor is 488.41 J.
Given data:
The mass of the person is, m = 50 kg.
The weight carried by the person is, W = 20 N.
The vertical height of ladder is, h = 3.0 m.
(a)
The energy possessed by an object by virtue of its position is called potential energy. The expression for the potential energy is given as,
[tex]PE = mgh[/tex]
here, g is the gravitational acceleration.
Solving as,
[tex]PE = 50 \times 9.8 \times 3.0\\\\PE = 1470 \;\rm J[/tex]
Thus, the potential energy of the can when it is at the top of the ladder is 1470 J.
(b)
And the kinetic energy is the energy of object by virtue of motion. And its expression is,
[tex]KE = \dfrac{1}{2} mv^{2}[/tex]
Here, v is the velocity of can.
Now, at 1 m height, its velocity is calculated as,
[tex]v^{2}=u^{2}+2gh\\\\v^{2}=0^{2}+2 \times 9.8 \times 1.0\\\\v = \sqrt{2 \times 9.8 \times 1} \\\\v=4.42 \;\rm m/s[/tex]
So, the kinetic energy is calculated as,
[tex]KE = \dfrac{1}{2} \times 50 \times (4.42)^{2}\\\\KE = 488.41 \;\rm J[/tex]
Thus, we can conclude that the kinetic energy of the can when it is 1.0 meter above the floor is 488.41 J.
Learn more about the kinetic energy here:
https://brainly.com/question/17858145
