Answer:
i[tex]\sqrt{2}[/tex] (or no solution if you haven't learned about imaginary numbers yet)
Step-by-step explanation:
The first thing you want to do is isolate x, or get x alone.
7x²+46=32
=> 7x²+46-46=32-46
=>7x²=-14
=>7x²÷7=-14÷7
=>x²=-2
If you have learned about imaginary numbers read on. If not, you have to realize that squaring any number can't result in a negative number. This means that there is no solution.
If you have learned about imaginary numbers, read on.
Now that you have x^2=-2, you can take the square root of both sides.
x=[tex]\sqrt{-2}[/tex]
Using a property about square roots (I don't know what it's called)
the equation becomes:
x=[tex]\sqrt{-1}\sqrt{2}[/tex]
And since [tex]\sqrt{-1}[/tex]=i, you can substitute in this value in to get x=i[tex]\sqrt{2}[/tex].
