Answer:
The work done by the electric force as one of the charges moves to an empty corner is:
[tex]W=0.129\: J[/tex]
Explanation:
The electric force between these points charges are:
[tex]F=k\frac{q_{1}q_{2}}{r^{2}}[/tex] (1)
Where:
k is the coulomb constant ([tex]9*10^{9} Nm^{2}C^{-2}[/tex])
q(1) the first charge
q(2) the second charge
r is the distance between them
The distance r is the distance of the diagonal of the square.
[tex]r=\sqrt{0.395^{2}+0.395^{2}}[/tex]
[tex]r=0.56\: m[/tex]
Then, using the equation (1) the electric force will be:
[tex]F=9*10^{9}\frac{16*10^{-12}}{0.56^{2}}[/tex]
[tex]\vec{F}=0.46\: N \vec{r}[/tex]
If we want to find the work done by the electric force we need to use the component of the force in the x or y direction because is the direction of the empty corner.
[tex]F_{x}=Fcos(45)[/tex]
[tex]W=F_{x}d[/tex]
[tex]W=0.46cos(45)0.395[/tex]
[tex]W=0.129\: J[/tex]
I hope it helps you!
