Na2SO4(aq) +CaCl2(aq) — CaSO4(s) + 2NaCl(aq) Ionic Equation: 2Na+ (aq) + S02-(aq) + Ca2+(aq) + 2C1- (aq) CaSO4(s) + 2Na+ (aq) + 2Cl- (aq) Now, let's write the net ionic equation: [?] + []=[] A. 2Na+(aq) C. 2C1-(aq) B. Ca2+ (aq) D. Na+ (aq)


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Na2SO4aq CaCl2aq CaSO4s 2NaClaq Ionic Equation 2Na aq S02aq Ca2aq 2C1 aq CaSO4s 2Na aq 2Cl aq Now lets write the net ionic equation A 2Naaq C 2C1aq B Ca2 aq D N class=

Respuesta :

Taking into account the definition of net ionic equation, the net ionic equation is:

SO²⁻(aq) + Ca²⁺(aq) → CaSO₄(s)

The net ionic equation is a chemical equation for a reaction that lists only the species that participate in the reaction.

In other words, an ionic equation is a chemical equation where electrolytes in aqueous solution are written as dissociated ions.

The balanced equation will be:

Na₂SO₄(aq) + CaCl₂(aq) → CaSO₄(s) + 2 NaCl(aq)

where (aq) means aqueous and (s) solid.

Taking into account that:

  • All Cl⁻, Br⁻ and I⁻ salts are soluble.  
  • All alkali metal salts are soluble. (for example, Li, Na, K salts).
  • Most of the sulfate salts (SO₄²⁻) are soluble. Exceptions to this include CaSO₄, BaSO₄, Ag₂SO₄, HgSO₄, and SrSO₄, which are slightly soluble. PbSO₄ is poorly soluble.

The total ionic equation in separated aqueous solution will be:

2 Na⁺(aq) + SO²⁻(aq) + Ca²⁺(aq) + 2 Cl⁻(aq) → CaSO₄(s) + 2 Na⁺(aq) + 2 Cl⁻(aq)

A spectator ion is an ion that appears both as a reactant and as a product in an ionic equation.

Spectator ions can be either cations (positively charged ions) or anions (negatively charged ions).

When writing a net ionic equation, spectator ions found in the original equation are ignored. Thus, the total ionic reaction is different from the net chemical reaction.

In this case, Na⁺ and Cl⁻ are the spectator ions because they appear unchanged in both the product and the reagent. So these ions cancel out by writing the net ionic equation and you get:

SO²⁻(aq) + Ca²⁺(aq) → CaSO₄(s)

In summary, the net ionic equation is:

SO²⁻(aq) + Ca²⁺(aq) → CaSO₄(s)

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