Respuesta :
Answer:
y = -6.57 10⁻³ m
Explanation:
The movement of water is an oscillation in the vertical direction that can be approximated as a simple harmonic movement
y = A cos (wt)
where the amplitude is A = 0.75 m and the angular velocity is related to the frequency
w = 2π f
w = 2π 1.25
w = 7.85 rad / s
we substitute
y = 0.75 cos (7.85 t)
we look for the amplitude for a time of t = 2.20 s, remember that the angles are in radians
y = 0.75 cos (7.85 2.20)
y = -0.00657 m
y = -6.57 10⁻³ m
The magnitude of the buoy’s displacement after 2.20 seconds is [tex]\bold { -6.57 10^{-3\ } m}[/tex].
The movement of water is an oscillation in the vertical direction can be calculated by
[tex]\bold { y = A cos (\omega t)}[/tex]
where,
A - amplitude = 0.75 m
[tex]\bold {\omega}[/tex] - angular velocity
Relationship between angular velocity and frequency
[tex]\bold { \omega = 2\pi f}\\\\ \bold { \omega = 2\pi 1.25}\\\\\bold { \omega = 7.85\ rad / s}[/tex]
Now put the values,
[tex]\bold { y = 0.75 cos (7.85 \times 2.2)}\\\\ \bold {y = -0.00657\ m}\\\\ \bold { y = \bold { -6.57 10^{-3\ } m}}[/tex]
The magnitude of the buoy’s displacement after 2.20 seconds is [tex]\bold { -6.57 10^{-3\ } m}[/tex].
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