Respuesta :

Space

Answer:

[tex]\displaystyle d = \sqrt{29}[/tex]

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right

Algebra I

  • Coordinates (x, y)

Algebra II

  • Distance formula: [tex]\displaystyle d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex]

Step-by-step explanation:

Step 1: Define

Point C(-5, -2)

Point D(0, -4)

Step 2: Find distance d

Simply plug in the 2 coordinates into the distance formula to find distance d

  1. Substitute in points [Distance Formula]:                                                       [tex]\displaystyle d = \sqrt{(0+5)^2+(-4+2)^2}[/tex]
  2. [√Radical] (Parenthesis) Add:                                                                        [tex]\displaystyle d = \sqrt{(5)^2+(-2)^2}[/tex]
  3. [√Radical] Evaluate exponents:                                                                     [tex]\displaystyle d = \sqrt{25+4}[/tex]
  4. [√Radical] Add:                                                                                               [tex]\displaystyle d = \sqrt{29}[/tex]
D=/29 that is your answer

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