Answer: 15?
Step-by-step explanation: i have no clue because im in 6th grade
Answer:
I think it's 46 or 6
Step-by-step explanation:
[tex]2(ab+bc+ca)=(a+b+c)^2-(a^2+6^2+c^2)[/tex]
=> [tex]2(ab+bc+ca)=1^2-2=-1[/tex]
=> [tex]ab+bc+ca=-1/2[/tex]
Given
[tex]a^3+b^3+c^3=3[/tex]
=> [tex]a^3+b^3+c^3-3abc+3abc=3[/tex]
=> [tex](a+b+c)(a^2+b^2+c^2-ab-bc-ca)+3abc=3[/tex]
=> [tex](a+b+c)(a^2+b^2+c2-(ab+bc+ca)+3abc=3[/tex]
=> [tex](1*(2-(-1/2) +3abc))=3[/tex]
=> [tex](2+1/2)+3abc=3[/tex]
=> [tex]abc=1/6[/tex]
Now
[tex]a^4+b^4+c^4[/tex]
[tex]=(a^2+b^2+c2^)^2-2)a^2b^2+b^2c^2+c^2a^2)[/tex]
[tex]= 2^2-2*(-1/12)[/tex]
[tex]=4+1/6=4\frac{1}{6}[/tex]
Yes, there is more things to do but I don't want it more challenging
Therefore
[tex]a^5+b^5+c^5=6-0=6[/tex]
Using memory and doing it a easier way, I think it's 46. Using paper and pencil, think it's 6
