Answer:
The cat must stand 0.96 m from the left side of the pivot to keep the seesaw balanced.
Explanation:
Given;
mass of the cat, m₁ = 5.2 kg
mass of the tuna, m₂ = 2.5 kg
length of the seesaw, L = 4.0 m
Apply the following approach;
x m <-------------2m ---------->
0------------------------------Δ------------------------------4m
↓ 2m ↓
5.2 kg 2.5 kg
Apply the principle of moment; anticlockwise moment = clockwise moment.
5.2(x ) = 2.5(2)
5.2x = 5
x = 5/5.2
x = 0.96 m
Therefore, the cat must stand 0.96 m from the left side of the pivot to keep the seesaw balanced.
