Respuesta :
The correct answer to the question is Option D. Ra-208
Let the parent atom be ʸₓB
From the question given above, we were told that the parent atom under goes alpha decay (i.e ⁴₂He) to produce ²⁰⁴₈₆Rn. The equation for the reaction is given below:
ʸₓB —> ²⁰⁴₈₆Rn + ⁴₂He
Next, we shall determine x, y and B. This can be obtained as follow:
for x:
x = 86 + 2
x = 88
For y:
y = 204 + 4
y = 208
For B:
ʸₓB => ²⁰⁸₈₈B => ²⁰⁸₈₈Ra
Thus, the complete equation is:
²⁰⁸₈₈Ra —> ²⁰⁴₈₆Rn + ⁴₂He
Therefore, the parent atom is ²⁰⁸₈₈Ra.
Option D. Ra-208 is the correct answer.
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