Respuesta :

Answer:

I think sin<GEJ IS equivalent to sin∠GFH

All that are equivalent to sin∠GFH is

D) cos(&lt;EGJ)

"Corresponding angles"

sin(&lt;GEJ)cos(&lt;FGH)cos(&lt;EGJ)

From the image JE and HF are parallel.

So angle GFH and angle GEJ are corresponding angles.

So they are equal.

so, sin(&lt;GFH) = sin(&lt;GEJ).

From triangle GFH, &lt;GFH+&lt;FGH = 90.

So, sin(&lt;GFH) =cos(&lt;FGH).

Again &lt;FGH = &lt;EGJ.

So, sin(&lt;GFH) =cos(&lt;EGJ)

All that are equivalent to sin∠GFH is cos(&lt;EGJ).

Thus, the correct answer is D.

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