Answer: 445.4 grams of carbon would be present.
Explanation:
According to avogadro's law, 1 mole of every substance contains avogadro's number [tex]6.023\times 10^{23}[/tex] of particles and weighs equal to its molecular mass.
To calculate the moles, we use the equation:
[tex]\text{Number of moles}=\frac{\text{Given mass}}{\text {Molar mass}}=\frac{1234g}{133g/mol}=9.28moles[/tex]
As 1 mole of [tex]C_4H_7NO_4[/tex] gives = 4 moles of carbon
Thus 9.28 moles of [tex]C_4H_7NO_4[/tex] gives = [tex]\frac{4}{1}\times 9.28=37.1[/tex] moles of carbon
Mass of carbon = [tex]moles\times {\text {Molar mass}}=37.1moles\times 12g/mol=445.4g[/tex]
Thus there are 445.4 grams of carbon would be present.
