Answer:
0 m
Explanation:
The question is incomplete, the complete question is attached.
Solution:
Velocity is the rate of change of displacement with respect to time. It is the ratio of change in displacement to change in time.
Give that the displacement x is given by the equation:
[tex]t=\sqrt{x}+3\\\\\sqrt{x} =t-3\\\\squaring\ both\ sides\ to\ get:\\\\(\sqrt{x}) ^2 =(t-3)^2\\\\x=t^2-6t+9\\\\The\ velocity\ v=\frac{dx}{dt} ;differentiating \ through\ with\ respect\ to\ t:\\\\\frac{dx}{dt} =\frac{d}{dt} (t^2-6t+9)\\\\v=2t-6\\\\At\ v=0:\\\\0=2t-6\\\\2t=6\\\\t=3\ s\\\\substitute\ t=3\ in \ x=t^2-6t+9\ to\ find\ displacement:\\\\x=3^2-6(3)+9\\\\x=0\ m[/tex]
