Answer:
The answer is below
Step-by-step explanation:
Firstly, let us find the value of x. Multiply the first equation by a and the second equation by b to get:
a²x + aby = ca (3)
b²x + aby = cb (4)
Subtract equation 4 from equation 3 to get:
x(a² - b²) = c(a - b)
but a² - b² = (a + b)(a - b)
x(a + b)(a - b) = c(a - b)
x(a + b) = c
[tex]x=\frac{c}{a+b}[/tex]
Secondly, let us find the value of y. Multiply the first equation by b and the second equation by a to get:
abx + b²y = cb (5)
abx + a²y = ca (6)
Subtract equation 5 from equation 6 to get:
y(a² - b²) = c(a - b)
but a² - b² = (a + b)(a - b)
y(a + b)(a - b) = c(a - b)
y(a + b) = c
[tex]y=\frac{c}{a+b}[/tex]
