Answer:
see explanation
Step-by-step explanation:
(a)
To find the x- intercepts , let y = 0 , that is
6x - x² = 0 ← factor out x from each term
x(6 - x) = 0
Equate each factor to zero and solve for x
x = 0
6 - x = 0 ⇒ x = 6
Coordinates of P (6, 0 )
(b)
The axis of symmetry is a vertical line, positioned at the midpoint of the zeros
x = [tex]\frac{0+6}{2}[/tex] = [tex]\frac{6}{2}[/tex] = 3
Equation of axis of symmetry is x = 3
(c)
Given a parabola in standard form y = ax² + bx + c ( a ≠ 0 )
Then the x- coordinate of the vertex is
[tex]x_{vertex}[/tex] = - [tex]\frac{b}{2a}[/tex]
y = 6x - x² = - x² + 6x ← is in standard form
with a = - 1, b = 6 , then
[tex]x_{vertex}[/tex] = - [tex]\frac{6}{-2}[/tex] = 3
Substitute x = 3 into y = 6x - x² for y- coordinate
y = 6(3) - 3² = 18 - 9 = 9
coordinates of maximum point = (3, 9 )
