Given:
A polynomial equation with rational coefficients has the roots [tex]5, \sqrt{6}, 3, -\sqrt{7}[/tex].
To find:
The two additional roots.
Solution:
According to the irrational root theorem, if [tex]a+\sqrt{b}[/tex] is a root of a polynomial, then [tex]a-\sqrt{b}[/tex] is also the root of that polynomial.
It is given that, [tex]\sqrt{6}\text{ and }-\sqrt{7}[/tex] are roots of a polynomial.
By using irrational root theorem, [tex]-\sqrt{6}\text{ and }\sqrt{7}[/tex] are also the roots of that polynomial.
Therefore, the two additional roots are [tex]-\sqrt{6}\text{ and }\sqrt{7}[/tex].
