Respuesta :

CintiaSalazar

Answer:

The volume of 9.0 M copper (II) sulfate stock solution needed to prepare 3.0 L of a 5.0 M solution is 1.667 L

Explanation:

Dilution is a process by which the concentration of a solute in solution is reduced by adding more solvent.

In other words, dilution is the procedure followed to prepare a less concentrated solution from a more concentrated one, and it simply consists of adding more solvent.

In a dilution the amount of solute does not vary. What varies in a dilution is the volume of the solvent: as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

The equation used in this case is:

Ci * Vi = Cf * Vf

where

  • Ci: initial concentration
  • Vi: initial volume
  • Cf: final concentration
  • Vf: final volume

In this case:

  • Ci: 9 M
  • Vi: ?
  • Cf: 5 M
  • Vf: 3 L

Replacing:

9 M*Vi= 5 M* 3 L

Solving:

[tex]Vi=\frac{5 M*3 L}{9 M}[/tex]

Vi= 1.667 L

The volume of 9.0 M copper (II) sulfate stock solution needed to prepare 3.0 L of a 5.0 M solution is 1.667 L

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