Answer:
F = 180 N
Explanation:
Given that,
Charge, q₁ = 10 μC
Charge, q₂ = 20 μC
The distance between the charges, r = 10 cm = 0.1 m
We need to find the magnitude of the electrostatic force. The formula for the electrostatic force is given by :
[tex]F=\dfrac{kq_1q_2}{r^2}\\\\F=\dfrac{9\times 10^9\times 10\times 10^{-6}\times 20\times 10^{-6}}{(0.1)^2}\\F=180\ N[/tex]
So, the magnitude of the electrostatic force is 180 N.
