Answer:
The probability that the event 'E'
P(E) = 0.2
Step-by-step explanation:
Explanation:-
Given that the sample space
S = { 1,2,3,4,5,6,7,8,9,10}
Total number of exhaustive events n(S) = 10
Given that the outcomes are equally likely
Let 'E' be the event { 5,8}
Favourable events n(E) = 2
The probability that the event 'E'
[tex]P(E) = \frac{n(E)}{n(S)}[/tex]
[tex]P(E) = \frac{2}{10} = \frac{1}{5} = 0.2[/tex]