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A rectangular swimming pool measures 40 ft by 60 ft and is surrounded by a path of uniform width around the four edges. The perimeter of the rectangle formed by the pool and the surrounding path is 248 ft. Determine the width of the path.

Respuesta :

piamoran5428

Answer:

6ft

Step-by-step explanation:

Lets x = the width of the path the surrounding path will add 2x to the pool dimension,therefore over all dimesion: (2x+40) by (2x+60) the overall perimeter (2x + 40) + 2(2x+60) = 248 Simplify divide by 2, result (2x+40) +(2x+60) = 124

Combine like terms 2x + 2x +40 +60 =124

4x + 100 = 124

4x=124 = 100

4x=24

x=24/4

x= 6ft is the width of the path

check this by finding the perimeter with these values; 2x = 12 ft

2 ( 12 + 40 ) + 2( 12 +60 )

2( 52 + 2(72)

104 + 144 = 248; confirms our solution of x= 6 ft

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