[tex]\Large\boxed{\tt Answer:~3x=2x+10;~x=10}[/tex]
[tex]\tt Step-by-step~explanation:[/tex]
Since it shows us that both ends of the segment in the middle bisects the sides of the triangle in the middle, we know that the segment in the middle is half of the hypotenuse (4x + 20).
[tex]\tt a)~ 3x =\frac{1}{2} (4x+20)[/tex]
Let's solve the right side of the equation by distributing[tex]\tt 0.5 (4x+20)\\4x*0.5=2x\\20*0.5=10\\\\b)~2x+10;~3x=2x+10[/tex]
Now, we can solve for x by moving the variable x to one side of the equation and everything else on the other side.
[tex]\tt 3x-(2x)=2x-(2x)+10\\\\c)~x=10[/tex]
