solve for x for the first and second question.
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Answer:
Step-by-step explanation:
I assume the figures are parallelograms, then
1). KL = MJ and
12x - 22 = 7x - 2
12x - 7x = 22 - 2
5x = 20
x = 4
2). m∠RQT + m∠QTS = 180°
(The picture is not clear and I might be wrong about coefficients by x for ∠RQT and ∠QTS)
(3x + 5)° + (9x - 17)° = 180°
12x - 12 = 180
12x = 192
x = 16