Answer:
because AB//EF//CD, using thales theorem in ABEF, we have:
[tex]\frac{12}{21}=\frac{15}{y}\\\\<=>y=\frac{15.21}{12}=26.25[/tex]
we also have: CD//EF//GH => using thales theorem in CDGH:
[tex]\frac{21}{x}=\frac{y}{10}\\\\<=>x=\frac{210}{y}=\frac{210}{26.25}=8[/tex]
with y = 26.25 => AB = 26.25 - 14 = 12.25
x = 8 => GH = 5.8 - 3 = 40 - 3 = 37
+) the perimeter of ABHG = AB + AC + CE + GE + GH + HF + DF + BD
= 12.25 + 12 + 21 + 8 + 37 + 10 + 26.25 + 15
= 141.5
Step-by-step explanation:
