Answer:
(A) the thermal efficiency of this engine is 66.44 %
(B) the power delivered by the engine in watts is 664,400 W
(C) The rate at which heat is rejected to the cold temperature sink is 335.6 kJ/s.
Explanation:
Given;
Input Heat received by the engine, [tex]P_{in}[/tex] = 1000 kJ/s
hot temperature, [tex]T_H[/tex] = 600 ⁰C = 600 + 273 = 873 K
cold temperature, [tex]T_C[/tex] = 20 ⁰C = 20 + 273 = 293 K
(A) the thermal efficiency of this engine;
[tex]\eta = 1 - \frac{T_C}{T_H} \\\\\eta = 1 - \frac{293}{873} \\\\\eta = 1 - 0.3356\\\\\eta = 0.6644 = 66.44 \%[/tex]
(B) the power delivered by the engine in watts;
[tex]P = \eta P_{in}\\\\P = 0.6644 \times \ 1000kJ/s \ \times \ \frac{1\ kW}{1\ kJ/s} \\\\P = 664.4 \ kW \\\\P = 664,400 \ W[/tex]
(C) The rate at which heat is rejected to the cold temperature sink;
[tex]Q_C = Q_H(1-\eta)\\\\Q_C = 1000\ kJ/s(1-0.6644)\\\\Q_C = 335.6 \ kJ/s[/tex]
