Answer:
[tex]6y^2\sqrt{2}[/tex]
Step-by-step explanation:
To simplify this equation, take out all the squares:
[tex]\sqrt{12}[/tex] = 2[tex]\sqrt{3} \s[/tex] (take out 4)
[tex]\sqrt{y^3}[/tex] = y[tex]\sqrt{y}[/tex] (take out y^2)
[tex]\sqrt{6y}[/tex] = [tex]\sqrt{6y}[/tex] (no squares)
Now, we can simply plug them back into the equation:
2[tex]\sqrt{3}[/tex] x y[tex]\sqrt{y}[/tex] x [tex]\sqrt{6y}[/tex]
If you want to put it all together, it will be:
2y[tex]\sqrt{18y^2}[/tex], which can further simplify into:
answer:
[tex]6y^2\sqrt{2}[/tex]
Hope this helps!!
