Answer:
The equilibrant force that will keep the object in equilibrium is;
A. 10 N to the left
Explanation:
The forces acting on the object are;
A 20 Newton force acting to pull the object horizontally to the left
A 30 Newton force acting to pull the object horizontally to the right
For equilibrium, we have;
The sum of forces acting on the object, ∑F = 0
Let '[tex]F_E[/tex]' represent the equilibrant force, with a convention of right = positive, we have;
At equilibrium, ∑F = 30 N - 20 N + [tex]F_E[/tex] = 0
∴ 30 N - 20 N + [tex]F_E[/tex] = 0
10 N = -[tex]F_E[/tex]
∴ [tex]F_E[/tex] = -10 N
With the convention that a force acting to the right = Positive, we have the equilibrant force, [tex]F_E[/tex] = -10 N which is negative, is acting towards the left;
∴ The equilibrant force that will keep the object in equilibrium, [tex]F_E[/tex] = 10 N acting to the left.
