Answer:
The volume of the metal is:
[tex]V_{t}=548\: cm^{3}[/tex]
Step-by-step explanation:
First, let's find the volume of the front face of the square:
[tex]V_{1}=12*7*1=84\: cm^{3}[/tex]
The back face is the same, so we have:
[tex]V_{2}=84\: cm^{3}[/tex]
The volume of the side faces will be:
[tex]V_{3}=7*10*1=70\: cm^{3}[/tex]
[tex]V_{4}=70\: cm^{3}[/tex]
And finally, the volume of the top and bottom side faces of the box will be:
[tex]V_{5}=12*10*1=120\: cm^{3}[/tex]
[tex]V_{6}=120\: cm^{3}[/tex]
The total volume of the metal will be:
[tex]V_{t}=V_{1}+V_{2}+V_{3}+V_{4}+V_{5}+V_{6}[/tex]
[tex]V_{t}=2(84)+2(70)+2(120)[/tex]
[tex]V_{t}=548\: cm^{3}[/tex]
I hope it helps you!
